Question

Base of a triangle is 9 and height is 5 .Base of another triangle is 10 and height of the triangle is 6 . Find the area of triangle.........​

Answer 1

Step-by-step explanation:

For first triangle it is

Area of traiangle=

$1 \div 2\times base \times height$

so,it is 1/2*9*5

=45/2=22.5

same for second traiangle.

1/2*10*6

=60/2=30.

Hope it helped u

Answer 2

✿solution✿☘️

given ;

base = 9

height = 5

$area \: of \: triangle \: = \frac{1}{2} \times base \: \times height \\ \\ area = \frac{1}{2} \times 9 \times 5 \\ \\ area \: of \: triangle = 22.5$

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$\huge\bold\red{ similarly in other ∆ }$

$area \: of \: triangle = \frac{1}{2} \times base \: \times height \\ \\ area = \frac{1}{2} \times 10 \times 6 \\ \\ area = 30 \: cm$