Question

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 9.Find the ratio of areas of these triangles.​

Answer 1

Answer:

=

Area(△PQR)

Area(△ABC)

=

2

1

×PM×QR

2

1

×AC×BC

=

2

1

×6×10

2

1

×5×9

=

4

3

Hence, Ratio of Area of △ABC:Area of △PQR=3:4

Answer 2

Step-by-step explanation:

solution:- Let the base , height and area of the first triangle be b1 , h1 and A1 respectively.

Let the base, height and area of second triangle be b2 , h2 and A2 respectively...

b1=9 ,h1= 5,b2= 10 and h2=6.

The ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights.

Therefore:- A1/A2 =b1 ×h1 /b2 ×h2

therefore:- A1/A2=9×5/10×6

Therefore:- A1/A2=3/4

Ans=The ratio of the areas of the triangles is 3:4.