Question

base of a triangle is 9 and height is 5 .base of another tiangle is 10 and height is 6 .find the ratio of areas of these triangle

Answer 1

$area \: of \: first \: tringle = \frac{1}{2} \times 9 \times 5 = 22.5 \\ area \: of \: second \: tringle = \frac{1}{2} \times 6 \times 10 = 30\\ \: \\ ratio \: = \frac{22.5}{30} \\ = 0.75$

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4