Question

base of a triangle is 9 and height is 5. base of another triangle is 10 and height is 6. find the ratio of areas of these triangl.

Answer 1

Area of 1st Δ = 1/2 x 9 x 5 = 45/2

Area of 2nd Δ = 1/2 x 10 x 6 = 60/2

ratio = 45/2 : 60/2

= 3:4

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Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4