Question

what is what is the power of torch bulb rated at 2.5 v and 500mA

Answer 1

500 mA = 1000×500=500000A=5×10^5A
v=2.5v
putting in formula
I=p/v
lv=p
5×10^5×2.5=p
p= 125×10^3W

Answer 2

Answer:

1.25W

Explanation:

Given,

   V=2.5v

    I=500mA= 500/1000=0.5A(mA is one thousandth of an ampere)

I =P/V

P=IV

 =2.5 x 0.5

P=  1.25W