base of a triangle is 9 and height is a 5 base of another triangle is 10 and height is 6 find the ratio of areas of these triangles
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here is your answer..
The required ratio is 3 : 4.
Let,
The triangle having 9 units as base and 5 units as height is ∆ ABC
And,the triangle having 10 units as base and 6 units as height is ∆ PQR
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Now,
Area of ∆ ABC = (base × height)/2
Area of ∆ ABC =(9×5)/2
Area of ∆ ABC = 45/2 = 22.5 unit²
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Area of ∆ PQR = (10×6)/2
Area of ∆ PQR = 10×3=30 unit²
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Ratio = 22.5 : 30
Ratio= 225:300
Ratio = 3:4
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