Question

EXERCISE 183
area of a trapezion whose parallel sides are 9 cm and 15 cm and the distance between them is 8 cm​

Answer 1

Explanation:

Given: Length of parallel sides are 9cm and 5cm

Height =8cm

Area of trapezium=

2

1

× Height ×(Sum of parallel sides)

=

2

1

×8cm×(9+5)cm

=

2

8+14

cm

2

=56cm

2

.

you can solve like this

Answer 2

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Given: Length of parallel sides are 9cm and 5cm

Height =8cm

Area of trapezium=

$\frac{1}{2} \times height \times (sum \: of \: parallel \: sides) \\ \\ acc \: to \: question \\ = \frac{1}{2} \times 8 \times (9 + 5) \\ = \frac{(8 + 14)}{2} {cm}^{2} \\ = 56 {cm}^{2}$

$\huge\underline\mathfrak\purple{Bts}$