Question

base of an isosceles triangle is 48 cm and its perimeter is 98 cm. Find its area.
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Answer 1

Answer:

Perimeter of isosceles triangle=98cm.

base of isosceles triangle=48

so,the hiportanace=48

height=98-48+48

=98-96

=2

area of triangle=1/2×h×b

=1/2×2×48

=48msquare

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Answer 2

$\huge\bold\color{blue}{\underbrace{\overbrace{\mathfrak{\color{red}{♡Answer♧}}}}}</p><p>$

Given :-

• Perimeter = 98 cm
• Base = 48 cm

To find :-

• Area of triangle

Let :-

• A,B,C be the sides
• B is base
• A = C [ ∵ Isosceles triangles has two equal sides.]

Then other two sides are :-

$\mathtt{ \implies \: A+B+C = 98}$

$\mathtt{ \implies \: A+48+A = 98.........(∵A=C)}$

$\mathtt{\implies 2A = 98- 48 }$

$\bold{\mathtt{\implies A = \frac{50}{2} }}$

$\mathtt{\implies A = 25}$

${\mathtt { \bold{ \therefore A = 25 cm \: \: \: and \: \: \: C = 25 cm}}}$

Finding area of triangle,

$\color{brown}{\mathtt{ {\boxed{ \bold {Semiperimeter = \: \frac{a + b + c}{2} }}}}}$

$\mathtt{Semiperimeter = \frac{25 + 25 + 48}{2} }$

$\mathtt{Semiperimeter = 49}$

Area of triangle:-

$\color{brown}{\boxed{\mathtt{ \bold{\bold{ \sqrt{s(s - a)(s - b)(s - c)}}}}}}$

$\implies \sqrt{49(49 - 25)(49 - 25)(49 - 48}$

$\implies \sqrt{49 \times 24 \times 24 \times 1 }$

$\implies \sqrt{7 \times 7 \times 3 \times 2 \times 2 \times 2 \times 3 \times 2 \times 2 \times 2}$

$\implies 7 \times 3 \times 2 \times 2 \times 2$

$\color{green}{\boxed{ \mathtt{ \bold{ \implies \: A\: = 168 \: {cm}^{2} }}}}$

∴Area of triangle is 168 cm².