base of issosceles triangle is 12cm and its perimeter is 32 , find its area?
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32 = a+b+c
= 12+x+x
=12+2x
32-12/2 = x
20/2 = x
10=x
area = √(32(32-12)(32-10)(32-10))
= √(32(20)(22)(22))
= 2×2×2×2×2×5×√11
=160√11
= 12+x+x
=12+2x
32-12/2 = x
20/2 = x
10=x
area = √(32(32-12)(32-10)(32-10))
= √(32(20)(22)(22))
= 2×2×2×2×2×5×√11
=160√11
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