base radius and height of a right circular cone are 8 cm and 6 CM respectively find its volume surface area and total surface area
Answers
Answered by
1
r = 8 cm
h = 6 cm
Volume = 1/3 πr²h
= 1/3 × 22/7× 8×8×6 = 401.92 cm³
T.S.A = πr (l + r) [l = √8²+6² = √100 = 10 cm]
= 8π( 10+8)
= 8π × 18 452.16 cm²
OK
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Answered by
0
Volume of a right circular cone=1/3π r^2 h
=1/3*22/7*8*8*6
=402.28cm^3
T.s.a of cone =(c.s.a+area of circle)of cone
=(πrl+πr^2)
First of all we have to find slant heigh(l)
l=(r^2+h^2)1/2
=(8*8+6*6)1/2
=(64+36)1/2
=10cm
T.s.a of cone =(22/7*8*10)+(22/7*8*8)
=(251.42+201.14)
=452.56cm^2
Hence your solution is completed !
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