Question

Based on equation E = – 2.178 × 10⁻¹⁸ J (z²/n²), certain conclusions are written. Which of them is not correct ?
a) Equation can be used to calculate the change in energy when the electron changes orbit
b) For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit
c) The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.
d) Larger the value of n, the larger is the orbit radius.

Answer 1

Answer :- option (d)

Explanation :- (a) this equation can't be used to find change in energy when the electron changes the oribit. For it we have to use , ∆E = RZ²hc(1/n₁² - 1/n₂²).

(b) yeah, of course if n = 1 , E has more negative value . But it means energy energy more energy required to remove electron from 1st orbit.

(c) negative sign in equation shows that electron are closely bound to the nucleus, means energy required to remove elsctron from definite orbit.

(d) it is correct, because n indicates orbit number where electron is present .
higher the value of n , larger will be size of orbit. And larger is the orbit radius.

Hence, option (d) is correct

Answer 2

Answer:

c) The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus. IS INCORRECT

Explanation: