There was a waste land near a locality in the shaape of parallelogram ABCD. The residents of the locality with the permission of concerd authorities dicided to fence the land and convert it into a park with shady tress, plants nd a small harbal, garden the perimitere of the land is 320 m. Length ab of the land is 100m the fancing has to be done only along sides ab, bc abd cd oof the land ad will be used as a gate
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Answered by
40
2(l+b)=320
(100+b)=320/2
b=160-100
b=60
AD will be the gate so,
320-AD=area to be fenced
320-60=260
Cost of fencing =260*€€€
(100+b)=320/2
b=160-100
b=60
AD will be the gate so,
320-AD=area to be fenced
320-60=260
Cost of fencing =260*€€€
Krishna8877047307:
Wrong
Answered by
133
Length=100 m
Perimeter=320 m=2*(l+b)
⇒320=2*(100+b)
⇒100+b=320/2
⇒100+b=160
⇒b=160-100
⇒∴b=60 m
NOW,
Perimeter of the field expect gate side=2*(l+b)-60 {∵gate side=60 m}
={2*(100+60)}-60
=(2*160)-60
=320-60
=260 m
NOW,
Cost of fencing=260*26 {∵rate=Rs 26/m}
= Rs 6,760 {Answer}
If it is helpful then please brainliest the answer otherwise comment me
Perimeter=320 m=2*(l+b)
⇒320=2*(100+b)
⇒100+b=320/2
⇒100+b=160
⇒b=160-100
⇒∴b=60 m
NOW,
Perimeter of the field expect gate side=2*(l+b)-60 {∵gate side=60 m}
={2*(100+60)}-60
=(2*160)-60
=320-60
=260 m
NOW,
Cost of fencing=260*26 {∵rate=Rs 26/m}
= Rs 6,760 {Answer}
If it is helpful then please brainliest the answer otherwise comment me
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