Question

Based on mole concept, calculate the mass of nitrogen gas and hydrogen gas required in
kilogram to produce1000 kg of ammonia by using the above chemical equation.​

Answer 1

Answer:

1000 kg of nitrogen, 1000 kg of hydrogen

Answer 2

44.426.37 grams of hydrogen and 412205.81 grams of nitrogen is used in the reaction to produce 1000kg ammonia

Explanation:

Balanced chemical equation is:

$N_{2}$ + 3$H_{2}$ ⇔ 2 $NH_{3}$

It is given that 1000 kg of ammonia is formed so first converting 1000kg into grams

The number of moles of ammonia can be known from the equation .

number of moles = mass given divided by atomic weight of one mole of the substance.

number of moles =  $\frac{mass given}{atomic mass}$

= 29,411.7 moles of ammonia are formed.

from the equation

I mole of nitrogen reacts to give 2 moles of ammonia

x mole of nitrogen reacts to give of ammonia

$\frac{2}{1}$ = $\frac{29411.7}{x}$

x = 14705.88 moles of nitrogen will be used hence mass can be calculated by multiplying the number of moles with atomic mass

14705.88× 28.013

= 412205.81 grams of nitrogen

Now the number of moles of hydrogen will be calculated

3 moles of H2 reacted to form 3 moles of NH3

X Moles of H2 reacted to form 29411.7 of ammonia.

= $\frac{2}{3}$ = $\frac{29411.7}{x}$

2x = 3× 29411.7

x     =  44117.55

the number of moles of hydrogen is known now the mass can be calculated by multiplying the number of moles with atomic mass

44117.55 × 1.007  

= 44.426.37 grams of hydrogen is used in the reaction.

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