Based on the following reaction:
BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)
If a reaction mixture contains 4.16 g of BaCl2 and 3.30 g of Na2SO4 how many moles of the precipitate will be formed?
A.
0.0200 moles
B.
0.0278 moles
C.
0.178 moles
D.
0.0241 moles
Answers
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Answer:
0.178
Explanation:
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