Question

Based on the following reaction:

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)

If a reaction mixture contains 4.16 g of BaCl2 and 3.30 g of Na2SO4 how many moles of the precipitate will be formed?

A.
0.0200 moles

B.
0.0278 moles

C.
0.178 moles

D.
0.0241 moles

Answer 1

Answer:

0.178

Explanation: