Question

based on the Law of conservation of mass, predict the minimum amount of magnesium
that will react with all 16.0 grams of oxygen to produce 40.3 grams of magnesium oxide.
Magnesium + Oxygen → Magnesium oxide
?g+16.0 g → 40.3 g​

Answer 1

Answer:

24.3 g

Explanation:

16 + x= 40.3

x= 40.3-16

x=24.3

Answer 2

The minimum amount of magnesium that will react with all 16.0 grams of oxygen to produce 40.3 grams of magnesium oxide is 24.3gm.

Explanation:

• The formula mass of magnesium oxide, MgO (40), is the sum of the mass of magnesium that is 24 and that of the mass of oxygen (16). It is fount that 24 g of Mg produces 40 g of MgO magnesium oxide when it reacts with 16 g of oxygen.
• The mass of the product which is formed is magnesium oxide.
• The mass formed will be exactly equal to the masses of the substances which reacts that is oxygen gas and magnesium metal
• Let X gm of magnesium react with 16 gm oxygen to form 40.3 gm of Magnesium oxide

The reaction involved will be -

Magnesium + Oxygen → Magnesium oxide

⇒X+16.0 g → 40.3 g

⇒16 +X= 40.3

⇒X= 40.3-16 gm

⇒ X=24.3gm

The minimum amount of magnesium that will react with all 16.0 grams of oxygen to produce 40.3 grams of magnesium oxide is 24.3gm.

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