Question

Based on VSEPR theory,the number of 90° F-Br-F bond angles in BrF3 is
(1)6
(2)4
(3)2
(4)0
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Answer 1

hii viewer here's ur answer

Zero.

For BrF5 steric number comes out to be 6 consisting of 5 bond pairs and 1 lone pair. It means we have distorted octahedral shape which is due to the repulsion caused by lone pair. It makes the geometry distorted. Hence there are no bond angles of perfect 90°.

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Answer 2

Answer:2

Explanation: Since the number of valence electrons in Br is 7 the 3 F atoms get a covalent sigma bond with the Br atom leaving out 2 lone pairs. The 2 lone pairs are close together above the Br and the 2 F atoms are 180° apart horizontally and one F atom is in vertical axis . So the number of F-Br-F bond with 90° will be 2.