Physics, asked by aruneshkumar14dec200, 2 months ago

battery of 10 volt carries 20,000 C of charge through a resistance of 20 Ω. The work done in

10 seconds is

(a) 2 × 103

joule (b) 2 × 105

joule

(c) 2 × 104

joule (d) 2 × 102

joule​

Answers

Answered by pranjalsaha2005
3

Answer:

(b) 2 * 10^5

Explanation:

work done = V * Q

                   = 10V * 20,000C

                   = 200,000J

                   = 2 * 10^5 J

Answered by adithyaaravalli
1

Answer:

W = V×Q

=b) 2×10^5

Explanation:

It is the right answer

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