bc(a²+1) +a(b2+c²) factorise
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Answered by
1
Answer:
Step-by-step explanation:ab(a²+b²-c²) -bc(c²-a²-b²) +ca(a²+b²-c²)
ab(a²+b²-c²) +bc(-c²+a²+b²) +ca(a²+b²-c²)
ab(a²+b²-c²) +bc(a²+b²-c²) +ca(a²+b²-c²)
(a²+b²-c²)(ab+bc+ca)
Or,
===========================
{a+(b-c)(b+c)} [ab +bc+ca]
Answered by
1
Answer:
a2bc+bc+ab2+ac2
a2bc+ac2+ab2+bc
ac(ab+c)+b(ab+c)
ac+b=0,ab+c=0
Step-by-step explanation:
I hope this answer may help you
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