Question

If the angle of prism is 60 degree and refractive index is 1.33, calculate and angle of

minimum deviation.​

Answer 1

Answer:

Minimum deviation δ=2i−A

where A is prism angle A=60

o

For minimum angle the angle of refraction should be half of prism angle.

So r=A/2=30

o

now using the snell's law

n

water

sini=n

glass

sinr

1.33sini=1.53sin30

i=35.11

o

Minimum deviation δ=2i−A

δ=2×35.11−60=10.2

o