Question

BC¯¯¯¯¯ is parallel to DE¯¯¯¯¯.



What is AC?



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A triangle with vertices labeled as A, D, and E. Side D E is the base and the top vertex is A. Sides A D and A E contain midpoints B and C, respectively. A line segment is drawn from point B to C. Side A B is labeled as 8. Side B D is labeled as 10. Side C E is labeled as 15.

Answer 1

AC = 12 cm

Step-by-step explanation:

since, BC ║ DE

AB = 8 cm

BD = 10 cm

CE = 15 cm

we need to find the AC

Using basic proportionality theorem ,

"If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio".

therefore,

$\frac{AB}{BD} = \frac{AC}{CE}$

putting the values

$\frac{8}{10} = \frac{AC}{15}$

cross multiplying

8×15 = AC×10

120 = AC×10

AC = $\frac{120}{10}$

AC = 12 cm

hence , AC = 12 cm

#Learn more:

In the given figure; if DE is parallel to BC(DE/BC) , Calculate X

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