Question

BD^2cm 5 cm . In the quadrilateral ABCD, if ZB = 90° and angle ACD = 90°, then AD^2 is:
a) AC^2 – AB^2 + BC^2
b) AC^2 - DC^2 + AB^2
c) AB^2 - BC^2 + CD^2
d) AB^2 – BC^2 + AC^2
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Answer 1

Answer:

omg what a question is this pal, looks really tough though