Harry lives at the top and Joe lives at the bottom of a hill 6 km long. Each Saturday they
meet at a bench on the hill somewhere between their houses. They find that, if they both
leave their houses at 10 am, they arrive at the bench at the same time. They both walk at 2
km/hr uphill and 4 km/hr downhill. After talking for an hour they each return home.
How much earlier does Joe arrive home than Harry?
A They arrive at the same time.
B Joe arrives 1⁄2 hour before Harry.
C Joe arrives 1 hour before Harry.
D Joe arrives 11⁄2 hours before Harry.
Answers
Answer:
a)They arrive at the same time .
Given : Harry lives at the top and Joe lives at the bottom of a hill 6 km long
if they both leave their houses at 10 am, they arrive at the bench at the same time.
They both walk at 2 km/hr uphill and 4 km/hr downhill.
After talking for an hour they each return home.
To Find : How much earlier does Joe arrive home than Harry?
Solution:
Total Distance = 6 km
Time to reach bench = T hrs
In going toward Bench
Harry goes down hill = 4 km/hr so distance covered = 4T km
Joe goes up hill = 2 km/hr so distance covered = 2T km
4T + 2T = 6
=> T = 1 hr
Harry goes down hill = 4 km
Joe goes up hill = 2 km
Hence they meet at 11 AM
and Leave at 12 PM
While returning
Joe need to go down hill 2 km
Time Take = 2/4 = 1/2 hr
Harry need to go uphill 4 km
Time Taken = 4/2 = 2 hr
Difference in Time = 2 - 1/2 = 1 1/2 hrs
Hence Joe arrives 1 1⁄2 hours before Harry.
Option D is correct
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