Math, asked by Beproductiv, 5 months ago

BE and CF are 2 equal altitudes of ∆ABC.Using RHS congruence rule,prove that the ∆ABC is isosceles​

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Answered by amanyadav090906
2

Answer:

Given: BE and CF are two equal altitudes of a triangle ABC. To Prove: ∆ABC is isosceles. ∴ ∠BCE = ∠CBF | C.P.C.T. ... Given: In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB.

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Answered by sam4915
2

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