Question

BE and CF are two equal altitudes of a triangle ABC. Prove that triangle ABC is a isosceles.​

Answer 1

Step-by-step explanation:

Angle BFC and CEB = 90dig.

BC = CB

FC = BE

Angle BCF = Angle CBE

Angle ECB = Angle FBC   {CPCT}

So, angle ABC = Angle ACB.

AB=AC   {sides opposite to equal angle is equal}

Hence ABC is Isosceles triangle Proved ...

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