Question

Beaker of radius 15 cm is filled with a liquid of surface tension 0.075 n/m. Force across an imaginary diameter on the surface of the liquid is:-

Answer 1

We know, surface tension of the liquid S= Force/ length.

Given S= 0.075 N/m

and radius of beaker= 15 cm= 0.15 m

So diameter of the surface of liquid= 2× 0.15= 0.30 m

F= S×l

 = 0.075×0.30= 2.25×10⁻²N

Answer 2

The force across an imaginary diameter on the surface of the liquid is 0.0225 N.

Explanation:

Given the radius of the beaker, r = 15 cm.

The surface tension of the liquid, T = 0.075 N/m.

Use the formula of surface tension as,

$T=\frac{F}{d}$

Here, F is the force  on an imaginary line drawn tangentially on the free surface the liquid and d is the diameter of the liquid on the surface.

diameter, d = 2 r = 2x15 cm = 30 cm.

substitute the given values, we get

$0.075N/m=\frac{F}{30\times10^-^2m}$

F = 0.0225 N.

Thus, the force across an imaginary diameter on the surface of the liquid is 0.0225 N.

#Learn More: Surface tension.

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