because I have to do it now. I never kept anything pending
Answers
Step-by-step explanation:
Given that;-
Two consecutive odd numbers such that one fifth of the smaller exceeds one ninth of the greater by 2.
To find:
Find the two consecutive odd numbers.
Solution:-
Let the Consecutive odd numbers be X and X+2
Greater number = X+2
smaller number = X
One - fifth of the smaller number = (1/5)X=X/5
One - ninth of the greater number
= (1/9)(X+2)
=> (X+2)/9
One fifth of the smaller exceeds the one ninth of the greater by 2
=>X/5=(X+2)/9+2
=>X/5-(X+2)/9=2
LCM of 5 and 9 is 45
=>[9X-5(X+2)]/45=2
=>(9X-5X-10)/45=2
=> (4X-10)/45=2
=>4X-10= 2×45
=>4X-10=90
=>4X=90+10
=>4X=100
=>X=100/4
=>X=25
=>X+2=25+2=27
Answer:-
The required two consecutive odd numbers are 25 and 27
Check:-
27>25
One fifth of the smaller =25/5=5
One ninth of the greater =27/9=3
One ninth of the greater+2=3+2=5
=One fifth of the smaller.
Answer:
25 and 27 are the numbers respectively