Math, asked by AZUKI6886, 1 year ago

Been divided into three parts such that half of the first part, one- third of the second part, and one-fourth of the third part are equal. The largest part is ? Problem 93/7 the sum of three numbers is 136.

Answers

Answered by sprao534

0

X/2=y/3=z/4
6x=4y=
X+y+z=136
X/+3/2x+2x=136
9x/2=136
9x=272
X=272/9

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