Question

Before 5 years one man is 7 times as his sons age.after 5 years the man is 3 times as his sons age.what are their present ages

Answer 1

Answer:

let the mans age be x

and sons age be y

according to question

before 5 years

mans age =x-5

sons age=y-5

now,

x-5=7(y-5)

x-5=7y-35

x-7y-5+35=0

x-7y+30=0

(or)x-7y=-30–----―――>(1)

after 5 years

mans age=x+5

sons age=y+5

now,

x+5=3(y+5)

x+5=3y+15

x-3y=15-5

x-3y=10――――――–------->(2)

solving 1 and 2

x-7y=-30

x-3y=+10 (on subtraction)

- + -

_______

-4y=-40

________

y=-40/-4

y=10

____

and now x-3y=10

x-3(10)=10

x-30=10

x=10+30

x=40

____

therefore,mans age=40

sons age=10

mark it as brainliest answer

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