Question

before

after

A block of mass m = 4.4 kg slides from left to right across =

a frictionless surface with a speed Vi 8.4 m/s. It collides in a perfectly elastic collision with a second block of mass M that is at rest. After the collision, the

4.4-kg block reverses direction, and its new speed is Vf= 2.5 m/s. What is V, the speed of the second

block after the collision?

Answer 1

Explanation:

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