Math, asked by chandurockzzzz, 10 months ago

before asked question answer :
Lhs:(1+tan^2¢)+(1+1/tan^2¢)=(1+tan^2¢)+(tan^2¢+1/tan^2¢)
=(1+tan^2¢).(1+1/tan^2¢)
=(1+tan^2¢).(tan^2¢+1/tan^2¢)
=(1+tan^2¢)^2/tan^2¢
=(sec^2¢)^2/tan^2¢
= 1/cos^4¢ x cos^2¢/sin^2¢
=1/sin^2¢.cos^2

Answers

Answered by leadha
2

Answer:

I don't know it sorry please check out in Google

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