before placing the raisins in water, the weight was 12g. the raisins were then removed, wiped well and weighed around 14.5g. what was the mass percentage of water imbibed by the raisins?
Answers
Answered by
0
the weight before applying water = 12g
the weight after applying water = 14.5g
the weight increase = 2.5g
% of weight increased = 2.5÷12 × 100
250 ÷ 12
20.833%
the weight after applying water = 14.5g
the weight increase = 2.5g
% of weight increased = 2.5÷12 × 100
250 ÷ 12
20.833%
Similar questions