Question

- BEGINNER - MATH SPT - 13 MINUTES AGO
Sum of all numbers between 500 to 1000 which are divisible by 13​

Answer 1

hi friend  

Step-by-step explanation:

Let's find the first number divisible by 13 in the natural numbers between 500 and 1000.

500/13=38, remainder =6

38×13=494

494+13=507 is the first in the series.

a=507

we have, d=13

last number is 1000/13=78,remainder 12

last term =78×13=988

from eq for nth term of ap

988=507+(n-1)×13

481=13n-13

13n=494

n=38

sum=38/2 (507+988)

=28405

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