Question

Beginning from rest, A man accelerates his car to reach a velocity of 60 meters per

second in 10 seconds. Then he applies the brakes and the velocity of the car decreases to 10

meters per second in the next 1 second. Calculate the acceleration of the car in both case​

Answer 1

Answer:

a) a= 1.2m/s2

b) a= -100m/s2

Answer 2

Answer:

i) 6 m/s²

ii) -50 m/s²

Explanation:

i) Given:

• Initial velocity (u) = 0 m/s  

• Final velocity (v) = 60 m/s

• Time (t) = 10 seconds

To find:

• Acceleration (a)

Method to find:

We can find the acceleration by using the 1st equation of motion.

v = u + at

⇒ 60 = 0 + (10)a

⇒ 60 = 10a

⇒ a = 60/10

⇒ a = 6 m/s²

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ii) Given:

• Initial velocity (u) = 60 m/s

• Final velocity (v) = 10 m/s

• Time (t) = 1 second

To find:

• Acceleration (a)

(The acceleration will be negative, as the car is slowing down)

Method to find:

We can find the deceleration by using the 1st equation of motion.

v = u + at

⇒ 10 = 60 + (1 * a)

⇒ 10 = 60 + a

⇒ a = -50 m/s

Hope it helps!