Question

Beginning from rest, Batman accelerates his Bat to reach a velocity of 60 meters per second in 10 seconds. Then he applies the brakes and the velocity of the Batmobile decreases to 10 meters per second in the next 1 second. Calculate the acceleration of the Batmobile in both cases.​

Answer 1

Answer:

Acceleration in 1st case = 6m/s²

Acceleration in 2nd case = -50m/s² (negative sign show retardation).

Explanation:

Solution:-

As it is given in 1st condition that the

initial velocity ,u = 0m/s

Final Velocity ,v = 60m/s

Time taken ,t = 10 s

we have to calculate the acceleration of the batman

Acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

substitute the value we get

→ a = 60-0/10

→ a = 60/10

→ a = 6m/s²

Hence, the acceleration in 1st case is 6m/s².

Now, calculating acceleration in 2nd case .

In second case the is given

Initial velocity ,u = 60m/s

Final Velocity ,v = 10m/s

Time taken ,t = 1

Acceleration in 2nd case ?

• a' = v-u/t

→ a' = 10-60/1

→ a' = -50/1

→ a' = -50m/s²

Here, negative sign show retardation

Hence, the acceleration of the batmobile in 2nd case is 50m/s².