Question

Benzene diazonium chloride is treated with hbf4

Answer 1

Hey dear,

● Answer -
It results in formation of fluorobenzene.

● Balz-Schiemann reaction -
- In this reaction, benzenediazonium chloride reacts with hydrofluoroboric acid to produce fluoborate
- Fluoborate on thermal distortion results in the formation of fluorobenzene.
- This reaction is used for production of fluorobenzene on large scale.

C6H5-N2-Cl + HBF4 ---> C6H5-N2-BF4
C6H5-N2-BF4 + heat ---> C6H5-F

[Refer to image attachment for better understanding]

Hope this helps...

Answer 2

"Benzene diazonium chloride  treated with  fluoroboric  acid to form substituted  product.

Followed  by  treated  with$\quad NaN{ O }_{ 2 }\quad$ to form nitro benzene and nitrogen.

The reaction is as follows.

Here copper (Cu) acts as a catalyst in the second process where $NaNO_2$ is used to initiate the process. The resultant product is nitrobenzene along with it there are some by-products such as nitrogen in the form of gas and Sodium tetrafluroborate."