Question

Benzene is dissolved in water to form a solution of 1L with a concentration of 55.6 mol/L. The initial concentration of Benzene in
mure organic liquid form is 800 mg/L. Calculate mole fraction for Benzene in the given solution​

Answer 1

sorry I didn't know…………………

Answer 2

answer

given = volume = 1Liter

           concentration = 55.6mol/L

           800g /l organic liqid

to find =  mole = ?

solution :-

mass of benzene  in 1 mole = 78g

in 800mg of benzene in organic solvent  97.5 moles of benzene present

now, for mole fraction of benzene in water =

=      $\frac{number of moles of benzene in water }{total number of moles of benzene }$

=  55.6 / 55.6 + 97.5

=  0.363

= mole fraction of benzene in organic solvent

= 97.5 / 55.6 + 97.5 = 0.636