Question

find the ratio of 5 th and 3 rd term in the expansion of (2+x)⁵​

Answer 1

Answer:

2/x²

Step-by-step explanation:

5 th term of (2+x)⁵ = ⁵C₍₅₋₁₎2⁽⁵⁻¹⁾x⁵⁻⁽⁵⁻¹⁾ = ⁵C₄2⁴x

3 rd term of (2+x)⁵ = ⁵C₍₃₋₁₎2⁽³⁻¹⁾x⁵⁻⁽³⁻¹⁾ = ⁵C₂2²x³

ratio of 5 th and 3 rd term = ⁵C₄2⁴x /  ⁵C₂2²x³  = 4×5/10x² = 2/x²