Question

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A math club has 61 members. The number of girls is 5 less than 2 times the number of boys. How many members are boys? How many members are girls?

Answer 1

let x be the boys and y be the girls
Acc. to question
x + y = 61 ....... (1)
Case 2
y = 2x - 5
on putting the value of y in equation 1 we get
x + 2x - 5 = 61
3x = 61 + 5
x = 66/3 = 22
On putting the value of x in equation 1 we get
22 + y = 61
y = 61 - 22
y = 39
Number of girls = 39
Number of boys = 22

Answer 2

Given that total number of members in club = 61.

B + G = 61   ----------- (1)

Given that number of girls is 5 less than 2 times the number of boys.

G = 2B - 5.   --------- (2)


Substitute (2) in (1), we get

 B  + 2B - 5= 61

3B - 5 = 61

3B = 66

B = 22.


Therefore the number of boys = 22.


Now,

Substitute B in (1), we get

B + G = 61

22 + G = 61

G = 61 - 22

G = 39.


Therefore the number of girls = 39.


Hope this helps!