Question

beta of a given transistor is 99. what is the value of alpha?

Answer 1

The answer to the question is 0.99

CALCULATION:

$\beta$ is called the dc current gain for common -emitter mode.

$\alpha$ is know as dC current gain for common base transistor.

The $\beta$ of a transistor is given as 99.

Hence, $\beta\ = 0.99$

We are asked to calculate the value of $\alpha$

The relation between $\beta\ and\ \alpha$ is written as -

                   $\beta=\frac{\alpha} {1-\alpha}$

                   $\beta-\alpha \beta=\alpha$

                   $\beta=\beta \alpha+\alpha$

                   $\beta= \alpha(1+\beta)$

                   $\alpha=\frac{\beta}{1+\beta}$

                         $=\frac{99}{1+99}$

                         $=0.99$

Hence, the value of alpha is 0.99.

Answer 2

Answer: The value is 0.99

Explanation:see the above image of solution

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