Question

find the value of a and b .
telll in nb pl,,zz

Answer 1

hey dear

here is your answer

Solution

LHS = ( 5+ 2√3 ) ( 7+4√3)

[ ( 5+2√3) ( 7-4√3 )] /

➗

(√7-4√3 ) ( 7+4√3)


[ 35 -20√3 +14 √3 +24]
➗

( 7^2 - ( 4√3^2)]


( 11-6√3 ) / [ 49 -48]


11-6√3


11-6√3 = a + b √3

hence a = 11

b = -6

hope it helps

thank you

Answer 2

5+2√3/7+4√3 rationalise this 
5+2√3/7+4√3*7-2√3/7-4√3
(5+2√3)(7-4√3)/(7)^2-(4√3)^2........a^2-b^2=(a+b)(a-b)
35-20√3+14√3-24/49-48
35-24-20√3+14√3
11-6√3
so,a=11 and b=6√3