Question

Between 200 and 400 leaves a remainder 2on division by 5?​

Answer 1

Answer:

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7=> 196 / 7 = ( n - 1 )

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7=> 196 / 7 = ( n - 1 )=> 28 = ( n - 1 )

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7=> 196 / 7 = ( n - 1 )=> 28 = ( n - 1 )=> n = 28 + 1 = 29

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7=> 196 / 7 = ( n - 1 )=> 28 = ( n - 1 )=> n = 28 + 1 = 29Hence the number of terms is 29.

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7=> 196 / 7 = ( n - 1 )=> 28 = ( n - 1 )=> n = 28 + 1 = 29Hence the number of terms is 29.Applying Sum formula we get,

The first term after 200 divisible by 7 is 203. The last term before 400 divisible by 7 is 399. The number of terms = ?=> l = a + ( n - 1 ) d=> 399 = 203 + ( n - 1 ) 7=> 399 - 203 = ( n - 1 ) 7=. 196 = ( n - 1 ) 7=> 196 / 7 = ( n - 1 )=> 28 = ( n - 1 )=> n = 28 + 1 = 29Hence the number of terms is 29.Applying Sum formula we get,Hence the sum of all the natural numbers divisible by 7 lying between 200 and 400 is 8729.