Math, asked by vk9155, 10 months ago

बहुपद 2x³-3kx²+4x-5 के सुनयन्को का योग 6 है तो k का मान क्या होगा​

Answers

Answered by TheNightHowler
2

Answer:

Heya mate

2 {x}^{3}  - 3k {x}^{2}  + 4x - 5 = 0 \\  \\ </em></strong><strong><em>P</em></strong><strong><em>utting \: x = 6 \: in \: the \: above \: equation \\  \\ 2 {(6)}^{3}  - 3k {(6)}^{2}  + 4(6) - 5 = 0 \\ 432 - 108k + 24 - 5 = 0 \\ 451 = 108k \\ k =  \frac{451}{108}  \\ k = 4.17

Hope it helps

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