Question

बहुपद : x2-2x-3 के शून्यक है।
(a) -3,1
(b) -3, -1
(c) 3,-1
(d) 3,1

Answer 1

Answer:

$Option \: \green {(c)} \: is \: correct$

Step-by-step explanation:

$Let \: p(x) = x^{2} - 2x - 3$

/* To find zero of p(x) ,we take p(x) = 0

$p(x) = 0$

$\implies x^{2} - 2x - 3 = 0$

$\implies x^{2} - 3x + 1x - 3 = 0$

$\implies x(x-3) + 1(x-3) = 0$

$\implies (x-3)(x+1) = 0$

$\implies x-3 = 0 \:Or \: x+1 = 0$

$\implies x = 3 \: Or \: x = -1$

Therefore.,

$Option \: \green {(c)} \: is \: correct$

•••♪

Answer 2

Step-by-step explanation:

given,

p(x)= x^2-2x-3=0

Now factorise

x^2-3x+x-3=0

x(x-3)+1(x-3)=0

(x-3) (x+1)=0

x-3=0

x=3

x+1=0

x=-1

hope this may help you bro mark me as brainlist (c)

So, it's option