Question

Bhai yar vii se x tak bata do

Answer 1

$\textbf{Answer}$

There are three expressions given -

2x^2 - 3y^2 ------(1)
5x^2 + 6y^2 ------(2)
-3x^2 - 4y^2 ------(3)

$\textbf{We need to add these expressions,}$

Lets add expressions (1), (2), (3)

(2x^2 - 3y^2) + (5x^2 + 6y^2) + (-3x^2 - 4y^2)

= (2x^2 + 5x^2 - 3x^2) + (6y^2 - 3y^2 - 4y^2)

= x^2(2 + 5 - 3) +y^2(6 - 3 - 4)

=x^2(4) + y^2(-1)

=4x^2 - y^2

$\textbf{Answer is }$ 4x^2 - y^2



$\textbf{Hope My Answer Helped}$
$\textbf{Thanks}$