Math, asked by prasangborse05, 2 months ago

bhaskar deposited rupees 10000 at 7% per annum in a fixed deposit scheme for two years and the nick deposited rupees 8000 at 8% per annum for 3 years the interest in each case is compounded annually who will get more compound interest how much more​

Answers

Answered by Anonymous
226

Solution :-

Case 1

Bhaskar deposited = Rs10000

Rate of interest = 7%

Time = 2 years

As we know that,

A = P ( 1 + R/100)^2

A = 10000( 1 + 7/100)^2

A = 10000( 107/100)^2

A = 10000 * 107/100 * 107/100

A = 107 * 107

A = Rs 11,449

Now,

CI = Amount - Principal

CI = 11449 - 10000

CI = Rs 1,449

Case 2

Nick deposited = Rs 8000

Rate of interest = 8%

Time = 3 years

As we know that,

A = P( 1 + R/100)^n

A = 8000 ( 1 + 8/100)^3

A = 8000 ( 108/100)^3

A = 8000 * 108/100 * 108/100 * 108/100

A = 8 * 108 * 108/10 * 108/100

A = 10077.69

Now,

CI = A - P

CI = 10077.69 - 8000

CI = 2077.69

Comparing the CI of case 1 and case 2

2077.69 - 1449 = 628.69

Hence, The case 2 CI is more than Case 1 CI by Rs628.69 .

Answered by prakshalshah0417
0

Solution :-

Case 1

Bhaskar deposited = Rs10000

Rate of interest = 7%

Time = 2 years

As we know that,

A = P ( 1 + R/100)^2

A = 10000( 1 + 7/100)^2

A = 10000( 107/100)^2

A = 10000 * 107/100 * 107/100

A = 107 * 107

A = Rs 11,449

Now,

CI = Amount - Principal

CI = 11449 - 10000

CI = Rs 1,449

Case 2

Nick deposited = Rs 8000

Rate of interest = 8%

Time = 3 years

As we know that,

A = P( 1 + R/100)^n

A = 8000 ( 1 + 8/100)^3

A = 8000 ( 108/100)^3

A = 8000 * 108/100 * 108/100 * 108/100

A = 8 * 108 * 108/10 * 108/100

A = 10077.69

Now,

CI = A - P

CI = 10077.69 - 8000

CI = 2077.69

Comparing the CI of case 1 and case 2

2077.69 - 1449 = 628.69

•°• The case 2 CI is more than Case 1 CI by Rs628.69

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