Math, asked by aakankshamahajan9, 1 year ago

Bhaskar is 4 times as old his son After 16 years we will be twice as old as his son find his son's present age

Answers

Answered by QuestionEverything
60
If son's age = x
then, Bhaskar's age = 4x
After 16 years!
Son's age = x+16
Bhaskar's age = 4x+16

Now, According to Ques,
4x+16 = 2(x+16)
4x+16 = 2x+32
2x = 16
x = 8
That is your answer!

aakankshamahajan9: thanks
Answered by abhi569
24
let the age of Bhaskar is 4x and the son's age =x

after 16years ,let Bhaskar age will be 2y and son age is y

converting in equation,

4x+16=2y -------1equation * 1
x+16=y --------2equation*4

4x+16=2y
4x+64=4y
- - -

-48=-2y

24=y

then put the value of y in -------2equation

x+16=24

x=24-16=8

x=8

son age =8years
and
Bhaskar age =8*4=32years




I hope this will help you






aakankshamahajan9: thanks
abhi569: your welcome akansha
abhi569: Thanks for choosing a brainlist answer
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