Question

Bhavana ate 1/4 of a cake while shefali ate3/4of it.who ate more cake and by how much?​

Answer 1

Answer: Shefali ate 200% more cake than Bhavana

Given: It is given that there is a cake and Bhavana ate 1/4 of it and Shefali ate 3/4 of it.

To Find: We have to find who ate more cake and by how much.

Step-by-Step Explanation:

Let the weight of cake be x grams.

Therefore, Bhavana ate  $\frac{x}{4}$ grams

and Shefali ate $\frac{3x}{4}$ grams

Step 1: We can see that Shefali has eaten more cake. The difference is          

=  $\frac{3x}{4} -\frac{x}{4}$

= $\frac{x}{2}$ grams

To Calculate how much percentage, she has eaten more than Bhavana we will use the following formula:

difference% = $\frac{difference}{initial} *100$

                    = $\frac{x/2}{x/4} *100$

                    = $200$ %

Therefore, Shefali ate 200% more cake than Bhavana.

To know more about the topic, refer to the links below:

https://brainly.in/question/33679035

https://brainly.in/question/36795631

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