Math, asked by harshvardhanjp, 9 months ago

What is the remainder when h(y)=4y^3-12y^2+14y-3 is divided by (2x-1)

Answers

Answered by ashishsingh822101
2

Answer:

g(x)=2x-1=0

          2x=1

             x=1/2

h(y)=4y^3-12y^2+14y-3

h(1/2)=4*(1/2)^3-12*(1/2)²+14*1/2-3

       =4*1/8-12*1/4+7-3

       =1/2-3+7-3

       =1/2-6+7

       =1/2+1

       =1+2/2

       =3/2 ans  

Step-by-step explanation:

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PLZ... MARK BRAINLIEST

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