Question

What is the remainder when h(y)=4y^3-12y^2+14y-3 is divided by (2x-1)

Answer 1

Answer:

g(x)=2x-1=0

          2x=1

             x=1/2

h(y)=4y^3-12y^2+14y-3

h(1/2)=4*(1/2)^3-12*(1/2)²+14*1/2-3

       =4*1/8-12*1/4+7-3

       =1/2-3+7-3

       =1/2-6+7

       =1/2+1

       =1+2/2

       =3/2 ans  

Step-by-step explanation:

I HOPE IT HELPS YOU

PLZ... MARK BRAINLIEST