What is the remainder when h(y)=4y^3-12y^2+14y-3 is divided by (2x-1)
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Answer:
g(x)=2x-1=0
2x=1
x=1/2
h(y)=4y^3-12y^2+14y-3
h(1/2)=4*(1/2)^3-12*(1/2)²+14*1/2-3
=4*1/8-12*1/4+7-3
=1/2-3+7-3
=1/2-6+7
=1/2+1
=1+2/2
=3/2 ans
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