Bhawna bought two fans for rs 3605. She sold one at a profit of 15% and the other at a loss of 9%. If Bhawna obtained the same amount for each fan, find the cost price of each fan
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Answer:
Cost=3605
cost of 1 fan÷3605/2=1802.5
profit from 1st fan=15/100×1802.5
selling price of 1st fan 270.375+1802.5=2072.875
loss com 2nd fan=9/100×1802.5=162.225
selling price of 2nd fan =1802.5-162.225=1640.275
tatal S.P=2072.875+1640.275=3713.15
profit=3713.15-3605=108.15
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The same amount for each fan, find the cost price of each fan.
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Let cost of table fans be Rs. x and Rs. y respectively
As per question,
=> x+y = 3605
=> y = 3605-x ...(1)
SP of,
=> First fan = x + 15% of x = Rs. 115x/100
=> Second fan = y - 9% of y = Rs. 91y/100
As per question,
=> 115x/100 = 91y/100
=> 115x = 91y
=> 115x = 91(3605-x) (From 1)
=> 115x = 328055-91x
=> 115x+91x = 328055
=> 206x = 328055
=> x = 328055/206 = Rs. 1592.50
∴ y = (3605-1592.50) = Rs. 2012.50
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