Bina hasrs 3600 in notes of denominations of rs 100 andrs 500.If the total number of notes is 24. Find the number of notes of each denominater. Solve it
Answers
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The number of 100 rupees notes is 21 and number of 500 rupees notes is 3
Solution:
Let "x" be the number of 100 rupees notes
Let "y" be the number of 500 rupees notes
The total number of notes is 24
Therefore,
x + y = 24 ------- eqn 1
Bina has Rs 3600 in notes of denominations of rs 100 and Rs 500
Thus, equation is framed as:
100x + 500y = 3600 --------- eqn 2
From eqn 1,
x = 24 - y ------- eqn 3
Substitute eqn 3 in eqn 2
100(24 - y) + 500y = 3600
2400 - 100y + 500y = 3600
400y = 1200
y = 3
Substitute y = 3 in eqn 3
x = 24 - 3
x = 21
Thus, number of 100 rupees notes is 21 and number of 500 rupees notes is 3
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